So, I have a problem that I can't get my head around. I am using the array function (PHP) based on your colors guide.
When I am using numbers 1=green, 2=blue, etc. it works - brilliantly, the output is the human readable response.
The problem I have is that my next drop-down-select is a file. filename.mp3 = Formal File Name. When I try the same code using the names, it still displays filename.mp3.
The code inside the array looks like this:
Again, thanks so much for a great product, it is helping my foray into coding and a great way to learn!
Mike
PS - this is the guide I am using
When I am using numbers 1=green, 2=blue, etc. it works - brilliantly, the output is the human readable response.
The problem I have is that my next drop-down-select is a file. filename.mp3 = Formal File Name. When I try the same code using the names, it still displays filename.mp3.
The code inside the array looks like this:
overload.mp3 => 'Overload',Again, thanks so much for a great product, it is helping my foray into coding and a great way to learn!
Mike
PS - this is the guide I am using
Hi Mike,
In PHP strings need to be quoted, integers don't. Please try
Bob
In PHP strings need to be quoted, integers don't. Please try
'overload.mp3' => 'Overload',Bob
Bob -
Perfection, figured it was something like that, but afraid to use a ' or a , or a ; (afraid PHP would catch the server on fire!)
Thanks so much!
Perfection, figured it was something like that, but afraid to use a ' or a , or a ; (afraid PHP would catch the server on fire!)
Thanks so much!
This topic is locked and no more replies can be posted.
