Hello!
The code below works perfectly, except it does not read the "inputText" field value in $query = "... LIKE ('inputText.value').
How can I get this value correctly in the same form?
Thanks.
The code below works perfectly, except it does not read the "inputText" field value in $query = "... LIKE ('inputText.value').
How can I get this value correctly in the same form?
…
div class="form_item"><div class="form_element cf_textbox">
<label class="cf_label" style="width: 0px;" ></label>
<input class="cf_inputbox" type="text" autocomplete="off" id="inputText" name="inputText">
<div class="clear"> </div></div>
<div class=form_item>
<div class="form_element cf_hidden" style="DISPLAY: none" >
<label class=cf_label>Hidden_field</label>
<?php
$db =& JFactory::getDBO();
$query = "select codigo_ProtGeral FROM #__protocolo_geral WHERE titulo LIKE ('inputText.value');";
$db->setQuery($query);
$result = $db->loadResult();
?>
<input type="hidden" name="codigo_ProtGeral" id="codigo_ProtGeral" value="<?php echo $result;?>" >
</div><div class=clear> </div></div>
<div class="form_item"><div class="form_element cf_button">
<input type="button" name="seguinte" onclick="goNext(codigo_ProtGeral.value);" value="Seguinte" >
<input value="Limpar" type="reset"></div>
<div class="clear"> </div></div>
…
Thanks.
Hi vsbr,
I think you have your PHP and JavaScript mixed up. All the PHP (and none of the JavaScript) will run before the page loads. So, there is no way to use a JavaScript value in a PHP command.
Bob
I think you have your PHP and JavaScript mixed up. All the PHP (and none of the JavaScript) will run before the page loads. So, there is no way to use a JavaScript value in a PHP command.
Bob
This topic is locked and no more replies can be posted.