Post your debug (without the chart)
this is not working error
Need more details
What error, did you take out the chart widget like I said?
I have found the answer for those who is saffuring the same issue
X field name returns values
Y field names return numbers therefore
X field names will be curso
Y field names will be Count(*) so it can count the records
i gues there is really lack of information in terms of chronoforms components and features published, i am looking basic things but i cannot finds some times in any where
thsnks
also do not forget to put
fields to retriew in DB read
curso
Count(*)
Well yes if you want to display the count you need to retrieve the count, that's not really chronoforms fault. Glad you figured it out.
So how to filter if count in filter is higher then 3
having count(*)>3
does not work for me there
Thanks for quick answer but it didint work for me
You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near ''comuna' GROUP BY `Data36.comuna`' at line 1
OK so apparently you need to use the HAVING clause and I don't think CF can handle that. I could be wrong, but in the meantime you have two options.
1) use a PHP block to take your array from $this->get("read_data#") and return an array of entries with count > 3
2) Make the database query yourself in PHP. https://docs.joomla.org/Special:MyLanguage/Selecting_data_using_JDatabase
i put {var:custom_code12.$row['2']}
to data provider
x field: comuna
y field: count(*)
does not work
easier way is order comuna/desc
and disabled 3 records
Should be {var:custom_code12.[n].comuna.field_name}
You haven't actually given Count(*) a name.